## How can I multiply more than 3 vectors at once in NumPy

numpy matrix multiplication

with numpy, what is the best way to compute the inner product of two vectors

numpy multiply matrix by vector element wise

numpy dot

numpy element wise multiplication

numpy array multiplication

numpy vector

I'm looking for a vectorised way to multiply more than 3 vectors in NumPy.

As an example,

X = np.array([1,2,3]) Y = np.array([4,5,6]) Z = np.array([7,8,9]) Multiply([X,Y,Z])

would produce as an output

np.array([28, 80, 162])

The vectors I want to multiply need not to be defined separately as I did above. The could be, for example, the rows (or columns) of a matrix, and in that case I would like to multiply all the rows (or columns) of such a matrix.

Helps appreciated :)

You can use the `reduce`

method of the ufunc:

>>> np.multiply.reduce((X, Y, Z)) array([ 28, 80, 162])

What's going on here is that the ufunc `np.multiply`

, which looks and acts like function, is technically an instance of the class `numpy.ufunc`

; all ufuncs have four special methods, one of them being `.reduce()`

, which does what you're looking for in this case and produces a 1d result from multiple same-length 1d arrays.

The default axis is 0; if you want to work along the other axis, just specify that:

>>> np.multiply.reduce((X, Y, Z), axis=1) array([ 6, 120, 504])

**numpy.linalg.multi_dot — NumPy v1.19 Manual,** Compute the dot product of two or more arrays in a single function call, while Depending on the shapes of the matrices, this can speed up the multiplication a lot. If the first argument is 1-D it is treated as a row vector. NumPy Basic Exercises, Practice and Solution: Write a NumPy program to multiply the values of two given vectors.

You can use `numpy.prod`

, which uses `multiply.reduce`

under the hood.

>>> np.prod([X, Y, Z], 0) array([ 28, 80, 162]) >>> np.prod([X, Y, Z], 1) array([ 6, 120, 504])

**numpy.multiply — NumPy v1.19 Manual,** outndarray, None, or tuple of ndarray and None, optional 3)) >>> x2 = np. arange(3.0) >>> np.multiply(x1, x2) array([[ 0., 1., 4.], [ 0., 4., 10.], [ 0. numpy.multiply() function is used when we want to compute the multiplication of two array. It returns the product of arr1 and arr2, element-wise. It returns the product of arr1 and arr2, element-wise.

Or very simply use the usual `*`

notation:

In [180]: X * Y * Z Out[180]: array([ 28, 80, 162])

In general, you can use as many arrays as you need:

In [181]: X * Y * Z * X * Y * Z Out[181]: array([ 784, 6400, 26244])

**numpy.dot — NumPy v1.19 Manual,** If both a and b are 1-D arrays, it is inner product of vectors (without complex If either a or b is 0-D (scalar), it is equivalent to multiply and using b = np.arange( 3*4*5*6)[::-1].reshape((5,4,6,3)) >>> np.dot(a, b)[2,3,2,1,2,2]� Transpose does not change anything. It is still the same 1-dimensional array. To overcome this problem (although it is not a problem per se because numpy will broadcast this vector in case of vector-matrix related operations), the 1-dimensional vector can be changed to a 2-dimensional vector using any of the following two methods: 1.

**numpy.matmul — NumPy v1.19 Manual,** This is a scalar only when both x1, x2 are 1-d vectors. Raises If either argument is N-D, N > 2, it is treated as a stack of matrices residing in the last two indexes and broadcast accordingly. After matrix multiplication the prepended 1 is removed. np.matmul([1,2], 3) Traceback (most recent call last): . Numpy can also be used as an efficient multi-dimensional container of data. for more information visit numpy documentation. Matrix Multiplication in Python. in this tutorial, we will see two segments to solve matrix. nested loop; using Numpy array

**Numerical & Scientific Computing with Python: Matrix Arithmetics in ,** Introduction with examples into Matrix-Arithmetics with the NumPy Module. Matrix addition; Matrix subtraction; Matrix multiplication; Scalar product; Cross product; and x = np.array([1,5,2]) >>> y = np.array([7,4,1]) >>> x + y array([8, 9, 3]) >>> x * y The addition of two vectors, in our example (see picture) x and y, may be� I’m looking to replace list comprehensions like the following with something more efficient and I was wondering if numpy can be used. [obj.matrix_world @ v.co for v in obj.data.vertices] I can do this, which is significantly faster, but still lacks the matrix multiplication, that needs to happen for each coordinate. coords = np.empty((len(obj.data.vertices), 3), 'f') obj.data.vertices

**20+ examples for NumPy matrix multiplication,** NumPy's array() method is used to represent vectors, matrices, and We'll use NumPy's matmul() method for most of our matrix multiplication operations. Let's define a 3�3 matrix and multiply it with a vector of length 3. However, if one dimension of a matrix is missing, NumPy would broadcast it to match� Eg. [1,2,3,4] Matrix: A matrix (plural matrices) is a 2-dimensional arrangement of numbers or a collection of vectors. Ex: [[1,2,3], [4,5,6], [7,8,9]] Dot Product: A dot product is a mathematical operation between 2 equal-length vectors. It is equal to the sum of the products of the corresponding elements of the vectors.

##### Comments

- Can you concatenate them using
`np.stack`

and then call`np.prod`

along the new axis? - I was kind of assuming the question concerned a variadic arg, i.e.
`multiply_arrays(*arrays)`

, or`multiply_arrays(arrays)`

(sequence arg). If not, this would definitely be simpler